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strings/detecting_english_programmatically.py
62 строки
2 KB
Suyash Dongre
Added doctest to detecting_english_programmatically.py (#11135)
06 ноя 2023, 15:14
Не верифицирован
06 ноя 2023, 15:14
fa508d7
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О чём код?
import os from string import ascii_letters LETTERS_AND_SPACE = ascii_letters + " \t\n" def load_dictionary() -> dict[str, None]: path = os.path.split(os.path.realpath(__file__)) english_words: dict[str, None] = {} with open(path[0] + "/dictionary.txt") as dictionary_file: for word in dictionary_file.read().split("\n"): english_words[word] = None return english_words ENGLISH_WORDS = load_dictionary() def get_english_count(message: str) -> float: message = message.upper() message = remove_non_letters(message) possible_words = message.split() matches = len([word for word in possible_words if word in ENGLISH_WORDS]) return float(matches) / len(possible_words) def remove_non_letters(message: str) -> str: """ >>> remove_non_letters("Hi! how are you?") 'Hi how are you' >>> remove_non_letters("P^y%t)h@o*n") 'Python' >>> remove_non_letters("1+1=2") '' >>> remove_non_letters("www.google.com/") 'wwwgooglecom' >>> remove_non_letters("") '' """ return "".join(symbol for symbol in message if symbol in LETTERS_AND_SPACE) def is_english( message: str, word_percentage: int = 20, letter_percentage: int = 85 ) -> bool: """ >>> is_english('Hello World') True >>> is_english('llold HorWd') False """ words_match = get_english_count(message) * 100 >= word_percentage num_letters = len(remove_non_letters(message)) message_letters_percentage = (float(num_letters) / len(message)) * 100 letters_match = message_letters_percentage >= letter_percentage return words_match and letters_match if __name__ == "__main__": import doctest doctest.testmod()