SQL-complete-tutorial
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Ex 17_OUTER JOIN between multiple tables.sql
27 строк · 603.0 Байт
1SELECT
2c.customer_id,
3c.first_name,
4o.order_id,
5sh.name AS shipper
6FROM customers c
7LEFT JOIN orders o
8ON c.customer_id = o.customer_id
9LEFT JOIN shippers sh
10ON sh.shipper_id = o.shipper_id;
11
12-- Return the data of order_date, order_id, first_name, shipper, status
13
14SELECT
15o.order_date,
16o.order_id,
17c.first_name AS customer,
18sh.name AS shipper,
19os.name AS status
20FROM orders o
21LEFT JOIN customers c
22ON c.customer_id = o.customer_id
23LEFT JOIN shippers sh
24ON sh.shipper_id = o.shipper_id
25LEFT JOIN order_statuses os
26ON os.order_status_id = o.status
27ORDER BY status;