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SuperclassConstructorException.java 
48 строк · 1.6 Кб
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/*
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 * Copyright (c) 2000, Oracle and/or its affiliates. All rights reserved.
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 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
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 *
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 * This code is free software; you can redistribute it and/or modify it
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 * under the terms of the GNU General Public License version 2 only, as
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 * published by the Free Software Foundation.
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 *
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 * This code is distributed in the hope that it will be useful, but WITHOUT
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 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
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 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
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 * version 2 for more details (a copy is included in the LICENSE file that
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 * accompanied this code).
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 *
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 * You should have received a copy of the GNU General Public License version
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 * 2 along with this work; if not, write to the Free Software Foundation,
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 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
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 *
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 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
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 * or visit www.oracle.com if you need additional information or have any
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 * questions.
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 */
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/*
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 * @test
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 * @bug 4350863 4358130
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 * @summary Verify that name of superclass constructor exception can be
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 * resolved correctly when instantiating a subclass.
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 * @author maddox
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 *
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 * @compile SuperclassConstructorException.java
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 */
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class Superclass {
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  public Superclass() throws java.io.IOException {}
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}
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class Subclass extends SuperclassConstructorException {}
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class SuperclassConstructorException {
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  public static void main(String args[]) {
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    try {
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      Object x = new Superclass(){};
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      Object y = new Subclass();
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    } catch (java.io.IOException e) {};
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  }
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}
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