/
niceSOFT
/
coreutils
Обзор
Документация
Войти
/
niceSOFT
/
coreutils
Код
Задачи
Вики
Пакеты
0
Релизы
0
Аналитика
Безопасность
master
tests/timeout/init-parent.sh
32 строки
1 KB
Collin Funk
timeout: don't exit immediately if the parent is the init process
14 мар 2026, 06:37
14 мар 2026, 06:37
e644eea
Код
Авторство
О чём код?
#!/bin/sh # Test the behavior of 'timeout' with the init process as its parent. # Copyright (C) 2026 Free Software Foundation, Inc. # This program is free software: you can redistribute it and/or modify # it under the terms of the GNU General Public License as published by # the Free Software Foundation, either version 3 of the License, or # (at your option) any later version. # This program is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU General Public License for more details. # You should have received a copy of the GNU General Public License # along with this program. If not, see <https://www.gnu.org/licenses/>. . "${srcdir=.}/tests/init.sh"; path_prepend_ ./src print_ver_ timeout newpids () { unshare --pid --fork --map-root-user "$@"; } newpids true || skip_ 'unshare --pid --fork --map-root-user is unavailable' # In coreutils-9.10 'timeout' would exit immediately if its parent was the init # process. This was discovered because Docker entrypoints have a process ID # of 1. newpids timeout .1 sleep 10 test $? = 124 || fail=1 Exit $fail