ilya.petrash/SimplePyScripts: Collection of various python script's.

RSSbashorg/RSSbashorg.py

16 строк351 B

Ilya Petrash

17 июн 2017, 05:10

17 июн 2017, 05:10e5d2218

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

__author__ = 'ipetrash'


import feedparser
rss = feedparser.parse('http://bash.im/rss/')
print(rss.feed.subtitle)

for entry in rss.entries:
    import html
    quote = html.unescape(entry.summary)
    quote = quote.replace('<br>', '\n')

    print('{0.title}: {0.link}\n{1}\n\n'.format(entry, quote))