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examples/src/main/python/ml/prefixspan_example.py
48 строк
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Huaxin Gao
[SPARK-24207][R] add R API for PrefixSpan
21 окт 2018, 22:32
21 окт 2018, 22:32
fc64e83
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# # Licensed to the Apache Software Foundation (ASF) under one or more # contributor license agreements. See the NOTICE file distributed with # this work for additional information regarding copyright ownership. # The ASF licenses this file to You under the Apache License, Version 2.0 # (the "License"); you may not use this file except in compliance with # the License. You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. # See the License for the specific language governing permissions and # limitations under the License. # """ An example demonstrating PrefixSpan. Run with: bin/spark-submit examples/src/main/python/ml/prefixspan_example.py """ # $example on$ from pyspark.ml.fpm import PrefixSpan # $example off$ from pyspark.sql import Row, SparkSession if __name__ == "__main__": spark = SparkSession\ .builder\ .appName("PrefixSpanExample")\ .getOrCreate() sc = spark.sparkContext # $example on$ df = sc.parallelize([Row(sequence=[[1, 2], [3]]), Row(sequence=[[1], [3, 2], [1, 2]]), Row(sequence=[[1, 2], [5]]), Row(sequence=[[6]])]).toDF() prefixSpan = PrefixSpan(minSupport=0.5, maxPatternLength=5, maxLocalProjDBSize=32000000) # Find frequent sequential patterns. prefixSpan.findFrequentSequentialPatterns(df).show() # $example off$ spark.stop()