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sklearn/cluster/_feature_agglomeration.py
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Christine P. Chai
DOC Correct many typos in code comments (#32666)
07 ноя 2025, 23:45
Не верифицирован
07 ноя 2025, 23:45
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""" Feature agglomeration. Base classes and functions for performing feature agglomeration. """ # Authors: The scikit-learn developers # SPDX-License-Identifier: BSD-3-Clause import numpy as np from scipy.sparse import issparse from sklearn.base import TransformerMixin from sklearn.utils.validation import check_is_fitted, validate_data ############################################################################### # Mixin class for feature agglomeration. class AgglomerationTransform(TransformerMixin): """ A class for feature agglomeration via the transform interface. """ def transform(self, X): """ Transform a new matrix using the built clustering. Parameters ---------- X : array-like of shape (n_samples, n_features) or \ (n_samples, n_samples) An M by N array of M observations in N dimensions or a length M array of M one-dimensional observations. Returns ------- Y : ndarray of shape (n_samples, n_clusters) or (n_clusters,) The pooled values for each feature cluster. """ check_is_fitted(self) X = validate_data(self, X, reset=False) if self.pooling_func == np.mean and not issparse(X): size = np.bincount(self.labels_) n_samples = X.shape[0] # a fast way to compute the mean of grouped features nX = np.array( [np.bincount(self.labels_, X[i, :]) / size for i in range(n_samples)] ) else: nX = [ self.pooling_func(X[:, self.labels_ == l], axis=1) for l in np.unique(self.labels_) ] nX = np.array(nX).T return nX def inverse_transform(self, X): """ Inverse the transformation and return a vector of size `n_features`. Parameters ---------- X : array-like of shape (n_samples, n_clusters) or (n_clusters,) The values to be assigned to each cluster of samples. Returns ------- X_original : ndarray of shape (n_samples, n_features) or (n_features,) A vector of size `n_samples` with the values of `X` assigned to each of the cluster of samples. """ check_is_fitted(self) unil, inverse = np.unique(self.labels_, return_inverse=True) return X[..., inverse]