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master
test/langtools/tools/javac/ConditionalWithVoid.java
20 строк
1 KB
Jan Lahoda
8232684: Make switch expressions final
12 ноя 2019, 09:32
12 ноя 2019, 09:32
29852ec
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/* * @test /nodynamiccopyright/ * @bug 4974927 8064464 * @summary The compiler was allowing void types in its parsing of conditional expressions. * @author tball * * @compile/fail/ref=ConditionalWithVoid.out -XDrawDiagnostics ConditionalWithVoid.java */ public class ConditionalWithVoid { public void test(Object o, String s) { // Should fail to compile since Object.wait() has a void return type. Poly case. System.out.println(o instanceof String ? o.hashCode() : o.wait()); // Should fail to compile since Object.wait() has a void return type. Standalone case. (o instanceof String ? o.hashCode() : o.wait()).toString(); // Should fail to compile since Object.wait() has a void return type. Poly case. System.out.println(switch (s) {case "" -> o.hashCode(); default -> o.wait();}); // Should fail to compile since Object.wait() has a void return type. Standalone case. (switch (s) {case "" -> o.hashCode(); default -> o.wait();}).toString(); } }