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man/html.xsl
37 строк
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Dan Nicholson
man: Use custom XSL stylesheet for HTML output
09 апр 2022, 04:25
09 апр 2022, 04:25
d5061dc
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<?xml version='1.0'?> <!--*-nxml-*--> <!-- Copyright © 2022 Endless OS Foundation LLC SPDX-License-Identifier: LGPL-2.0+ This library is free software; you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation; either version 2 of the License, or (at your option) any later version. This library is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details. You should have received a copy of the GNU Lesser General Public License along with this library. If not, see <https://www.gnu.org/licenses/>. --> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:import href="http://docbook.sourceforge.net/release/xsl/current/html/docbook.xsl"/> <!-- translate man page references to links to html pages --> <xsl:template match="citerefentry"> <a> <xsl:attribute name="href"> <xsl:value-of select="refentrytitle"/> <xsl:text>.html</xsl:text> </xsl:attribute> <xsl:call-template name="inline.charseq"/> </a> </xsl:template> </xsl:stylesheet>