/
githubmirror
/
interviews
Обзор
Документация
Войти
/
githubmirror
/
interviews
Код
Запросы
0
Пакеты
0
Релизы
0
Аналитика
Безопасность
master
leetcode/bit-manipulation/Utf8Validation.java
60 строк
2 KB
Kevin Naughton Jr
finish renaming files and directories
27 мар 2018, 19:52
27 мар 2018, 19:52
ec6dfb5
Код
Авторство
О чём код?
// A character in UTF8 can be from 1 to 4 bytes long, subjected to the following rules: // For 1-byte character, the first bit is a 0, followed by its unicode code. // For n-bytes character, the first n-bits are all one's, the n+1 bit is 0, followed by n-1 bytes with most significant 2 bits being 10. // This is how the UTF-8 encoding would work: // Char. number range | UTF-8 octet sequence // (hexadecimal) | (binary) // --------------------+--------------------------------------------- // 0000 0000-0000 007F | 0xxxxxxx // 0000 0080-0000 07FF | 110xxxxx 10xxxxxx // 0000 0800-0000 FFFF | 1110xxxx 10xxxxxx 10xxxxxx // 0001 0000-0010 FFFF | 11110xxx 10xxxxxx 10xxxxxx 10xxxxxx // Given an array of integers representing the data, return whether it is a valid utf-8 encoding. // Note: // The input is an array of integers. Only the least significant 8 bits of each integer is used to store the data. This means each integer represents only 1 byte of data. // Example 1: // data = [197, 130, 1], which represents the octet sequence: 11000101 10000010 00000001. // Return true. // It is a valid utf-8 encoding for a 2-bytes character followed by a 1-byte character. // Example 2: // data = [235, 140, 4], which represented the octet sequence: 11101011 10001100 00000100. // Return false. // The first 3 bits are all one's and the 4th bit is 0 means it is a 3-bytes character. // The next byte is a continuation byte which starts with 10 and that's correct. // But the second continuation byte does not start with 10, so it is invalid. public class Utf8Validation { public boolean validUtf8(int[] data) { int count = 0; for(int i : data) { if(count == 0) { if((i >> 5) == 0b110) { count = 1; } else if((i >> 4) == 0b1110) { count = 2; } else if((i >> 3) == 0b11110) { count = 3; } else if((i >> 7) == 0b1) { return false; } } else { if((i >> 6) != 0b10) { return false; } count--; } } return count == 0; } }