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string/tst-strlen.c
57 строк
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Adhemerval Zanella Netto
Use '%z' instead of '%Z' on printf functions
22 сен 2022, 14:48
22 сен 2022, 14:48
de477ab
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/* Make sure we don't test the optimized inline functions if we want to test the real implementation. */ #undef __USE_STRING_INLINES #include <stdio.h> #include <string.h> int do_test (void) { static const size_t lens[] = { 0, 1, 0, 2, 0, 1, 0, 3, 0, 1, 0, 2, 0, 1, 0, 4 }; char basebuf[24 + 32]; size_t base; for (base = 0; base < 32; ++base) { char *buf = basebuf + base; size_t words; for (words = 0; words < 4; ++words) { size_t last; memset (buf, 'a', words * 4); for (last = 0; last < 16; ++last) { buf[words * 4 + 0] = (last & 1) != 0 ? 'b' : '\0'; buf[words * 4 + 1] = (last & 2) != 0 ? 'c' : '\0'; buf[words * 4 + 2] = (last & 4) != 0 ? 'd' : '\0'; buf[words * 4 + 3] = (last & 8) != 0 ? 'e' : '\0'; buf[words * 4 + 4] = '\0'; if (strlen (buf) != words * 4 + lens[last]) { printf ("\ strlen failed for base=%zu, words=%zu, and last=%zu (is %zd, expected %zd)\n", base, words, last, strlen (buf), words * 4 + lens[last]); return 1; } if (strnlen (buf, -1) != words * 4 + lens[last]) { printf ("\ strnlen failed for base=%zu, words=%zu, and last=%zu (is %zd, expected %zd)\n", base, words, last, strnlen (buf, -1), words * 4 + lens[last]); return 1; } } } } return 0; } #include <support/test-driver.c>