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test/regeq.awk
29 строк
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Arnold D. Robbins
Move to gawk-3.1.0.
16 июл 2010, 14:09
16 июл 2010, 14:09
bc70de7
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#Date: Sat, 8 May 1999 17:42:20 +0200 #From: Iva Cabric <ivac@fly.srk.fer.hr> #To: bug-gnu-utils@gnu.org #Cc: arnold@gnu.org #Subject: Problem in gawk with match # #Hello, # #gawk reports fatal error in match when first character in regexp is "=" : # #$ gawk '{ where = match($0, /=a/); print where}' #gawk: cmd. line:1: { where = match($0, /=a/); print where} #gawk: cmd. line:1: ^ parse error #gawk: cmd. line:1: fatal: match() cannot have 0 arguments # #Using "\=" instead "=" works without problems : # #$ gawk '{ where = match($0, /\=a/); print where}' #sdgfa #0 #asdfds=a #7 # #Other versions of awk have no problems with "/=/" (except oawk on SunOS). # #-- # @ # { where = match($0, /=a/); print where}