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awklib/eg/network/geturl.awk
24 строки
787 B
Arnold D. Robbins
Move to gawk-3.1.0.
16 июл 2010, 14:09
16 июл 2010, 14:09
bc70de7
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BEGIN { if (ARGC != 2) { print "GETURL - retrieve Web page via HTTP 1.0" print "IN:\n the URL as a command-line parameter" print "PARAM(S):\n -v Proxy=MyProxy" print "OUT:\n the page content on stdout" print " the page header on stderr" print "JK 16.05.1997" print "ADR 13.08.2000" exit } URL = ARGV[1]; ARGV[1] = "" if (Proxy == "") Proxy = "127.0.0.1" if (ProxyPort == 0) ProxyPort = 80 if (Method == "") Method = "GET" HttpService = "/inet/tcp/0/" Proxy "/" ProxyPort ORS = RS = "\r\n\r\n" print Method " " URL " HTTP/1.0" |& HttpService HttpService |& getline Header print Header > "/dev/stderr" while ((HttpService |& getline) > 0) printf "%s", $0 close(HttpService) }