githubmirror/bash-completion

completions/timeout

38 строк944 B

Ville Skyttä

*: remove spaces immediately within $()

14 апр 2019, 19:07

14 апр 2019, 19:0790e380b

# timeout(1) completion                                    -*- shell-script -*-

_timeout()
{
    local cur prev words cword split i found=false
    _init_completion -s || return

    for (( i=1; i <= COMP_CWORD; i++ )); do
        if [[ ${COMP_WORDS[i]} != -* && ${COMP_WORDS[i-1]} != = ]]; then
            if $found; then
                _command_offset $i
                return
            fi
            found=true
        fi
        [[ ${COMP_WORDS[i]} == -@(-kill-after|-signal|!(-*)[ks]) ]] && ((i++))
    done

    case $prev in
        --help|--version|--kill-after|-!(-*)k)
            return
            ;;
        --signal|-!(-*)s)
            _signals
            return
            ;;
    esac

    $split && return

    if [[ $cur == -* ]]; then
        COMPREPLY=( $(compgen -W '$(_parse_help "$1")' -- "$cur") )
        [[ $COMPREPLY == *= ]] && compopt -o nospace
    fi
} &&
complete -F _timeout timeout

# ex: filetype=sh