githubmirror/bash-completion

completions/shellcheck

51 строка1 KB

Ville Skyttä

*: remove spaces immediately within $()

14 апр 2019, 19:07

14 апр 2019, 19:0790e380b

# bash completion for shellcheck(1)                        -*- shell-script -*-

_shellcheck_optarg()
{
    local args=$("$1" --help 2>&1 | \
        command sed -e 's/,/ /g' -ne 's/^.*'$2'\>.*(\([^)]*\)).*/\1/p')
    COMPREPLY+=( $(compgen -W '$args' -- "$cur") )
}

_shellcheck()
{
    local cur prev words cword split
    _init_completion -s || return

    case $prev in
        --version|-!(-*)V*)
            return
            ;;
        --exclude|-!(-*)e)
            return
            ;;
        --format|-!(-*)f)
            local args=$("$1" --format=nonexistent-format /dev/null 2>&1 | \
                command sed -ne '/^Supported formats/,//p' | \
                command sed -ne '/^[[:space:]]/p')
            COMPREPLY=( $(compgen -W '$args' -- "$cur") )
            return
            ;;
        --color|-!(-*)C)
            _shellcheck_optarg "$1" --color
            return
            ;;
        --shell|-!(-*)s)
            _shellcheck_optarg "$1" --shell
            return
            ;;
    esac

    $split && return

    if [[ "$cur" == -* ]]; then
        COMPREPLY=( $(compgen -W '$(_parse_help "$1")' -- "$cur") )
        [[ $COMPREPLY == *= ]] && compopt -o nospace
        return
    fi

    _filedir
} &&
complete -F _shellcheck shellcheck

# ex: filetype=sh