githubmirror/bash-completion

completions/sh

36 строк885 B

Ville Skyttä

*: remove spaces immediately within $()

14 апр 2019, 19:07

14 апр 2019, 19:0790e380b

# POSIX sh(1) completion                                   -*- shell-script -*-

_sh()
{
    local cur prev words cword
    _init_completion || return

    case $prev in
        -c)
            return
            ;;
        -o|+o)
            COMPREPLY=( $(compgen -W 'allexport errexit ignoreeof monitor
                noclobber noglob noexec nolog notify nounset verbose vi
                xtrace' -- "$cur") )
            return
            ;;
    esac

    local opts="-a -b -C -e -f -h -i -m -n -o -u -v -x"
    if [[ "$cur" == -* ]]; then
        COMPREPLY=( $(compgen -W "$opts -c -s" -- "$cur") )
        return
    elif [[ "$cur" == +* ]]; then
        COMPREPLY=( $(compgen -W "${opts//-/+}" -- "$cur") )
        return
    fi

    local args ext=
    _count_args "" "@(-c|[-+]o)"
    [[ $args -eq 1 ]] && ext=sh
    _filedir $ext
} &&
complete -F _sh sh

# ex: filetype=sh