githubmirror/bash-completion

completions/gpg

38 строк1 KB

Ville Skyttä

*: remove spaces immediately within $()

14 апр 2019, 19:07

14 апр 2019, 19:0790e380b

# bash completion for gpg                                  -*- shell-script -*-

_gpg()
{
    local cur prev words cword
    _init_completion || return

    case $prev in
        --sign|--clearsign|--decrypt-files|--load-extension|-!(-*)s)
            _filedir
            return
            ;;
        --export|--sign-key|--lsign-key|--nrsign-key|--nrlsign-key|--edit-key)
            # return list of public keys
            COMPREPLY=( $(compgen -W "$($1 --list-keys 2>/dev/null | command sed -ne \
                's@^pub.*/\([^ ]*\).*$@\1@p' -ne \
                's@^.*\(<\([^>]*\)>\).*$@\2@p')" -- "$cur") )
            return
            ;;
        --recipient|-!(-*)r)
            COMPREPLY=( $(compgen -W "$($1 --list-keys 2>/dev/null | command sed -ne \
                's@^.*<\([^>]*\)>.*$@\1@p')" -- "$cur") )
            if [[ -e ~/.gnupg/gpg.conf ]]; then
                COMPREPLY+=( $(compgen -W "$(command sed -ne \
                    's@^[ \t]*group[ \t][ \t]*\([^=]*\).*$@\1@p' \
                    ~/.gnupg/gpg.conf)" -- "$cur") )
            fi
            return
        ;;
    esac

    if [[ "$cur" == -* ]]; then
        COMPREPLY=( $(compgen -W '$($1 --dump-options)' -- "$cur") )
    fi
} &&
complete -F _gpg -o default gpg

# ex: filetype=sh