githubmirror/bash-completion

completions/chmod

40 строк867 B

Ville Skyttä

*: make _parse_usage fallbacks more concise

14 апр 2019, 21:48

14 апр 2019, 21:483c10d4d

# chmod(1) completion                                      -*- shell-script -*-

_chmod()
{
    local cur prev words cword split
    _init_completion -s || return

    case $prev in
        --help|--version)
            return
            ;;
        --reference)
            _filedir
            return
            ;;
    esac

    $split && return

    # Adapted from coreutils 8.28 chmod man page
    local modearg="-@(@(+([rwxXst])|[ugo])|+([0-7]))"

    if [[ $cur == -* && $cur != $modearg ]]; then
        local opts=$(_parse_help "$1")
        COMPREPLY=( $(compgen -W '${opts:-$(_parse_usage "$1")}' -- "$cur") )
        [[ $COMPREPLY == *= ]] && compopt -o nospace
        return
    fi

    local args
    _count_args "" "" "$modearg"

    case $args in
        1) ;;  # mode
        *) _filedir ;;
    esac
} &&
complete -F _chmod chmod

# ex: filetype=sh