src/main/java/com/thealgorithms/strings/ValidParentheses.java - master - NikolayIvkin/TheAlgorithms

src/main/java/com/thealgorithms/strings/ValidParentheses.java

59 строк2 KB

Taranjeet Singh Kalsi

Add another method to check valid parentheses in ValidParentheses.java (#5616)

07 окт 2024, 21:48

07 окт 2024, 21:484a5bf39

package com.thealgorithms.strings;
//        Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine
//        if the input string is valid. An input string is valid if: Open brackets must be closed by
//        the same type of brackets. Open brackets must be closed in the correct order. Every close
//        bracket has a corresponding open bracket of the same type.

public final class ValidParentheses {
    private ValidParentheses() {
    }
    public static boolean isValid(String s) {
        char[] stack = new char[s.length()];
        int head = 0;
        for (char c : s.toCharArray()) {
            switch (c) {
            case '{':
            case '[':
            case '(':
                stack[head++] = c;
                break;
            case '}':
                if (head == 0 || stack[--head] != '{') {
                    return false;
                }
                break;
            case ')':
                if (head == 0 || stack[--head] != '(') {
                    return false;
                }
                break;
            case ']':
                if (head == 0 || stack[--head] != '[') {
                    return false;
                }
                break;
            default:
                throw new IllegalArgumentException("Unexpected character: " + c);
            }
        }
        return head == 0;
    }
    public static boolean isValidParentheses(String s) {
        int i = -1;
        char[] stack = new char[s.length()];
        String openBrackets = "({[";
        String closeBrackets = ")}]";
        for (char ch : s.toCharArray()) {
            if (openBrackets.indexOf(ch) != -1) {
                stack[++i] = ch;
            } else {
                if (i >= 0 && openBrackets.indexOf(stack[i]) == closeBrackets.indexOf(ch)) {
                    i--;
                } else {
                    return false;
                }
            }
        }
        return i == -1;
    }
}